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Compute: - Mathematics

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Question

Compute:

`(27/64)^(-2/3)`

Sum

Solution

`(27/64)^(-2/3)=[[(3^3))/((4^3))]^(-2/3)`

                 `=3^(3xx-2/3)/4^(3xx(-2)/3)=3^-2/4^-2`

                 `=4^2/3^2=(4xx4)/(3xx3)=16/9`

                 `=1 7/9`

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More About Exponents
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Chapter 2: Exponents - Exercise 2 (B) [Page 33]

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Selina Concise Mathematics [English] Class 8 ICSE
Chapter 2 Exponents
Exercise 2 (B) | Q 1.11 | Page 33
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