Advertisements
Advertisements
Question
Prove that:
`1/(1+"x"^("a"-"b"))+1/(1+"x"^("b"-"a"))=1`
Solution
`1/(1+"x"^("a"-"b"))+1/(1+"x"^("b"-"a"))=1`
`"L"."H"."S".=1/(1+"x"^("a"-"b"))+1/(1+"x"^("b"-"a")`
`=1/("x"^("a"-"a")+"x"^("a"-"b"))+1/("x"^("b"-"b")+"x"^("b"-"a")`
`=1/("x"^"a"."x"^-"a"+"x"^"a"."x"^-"b")+1/("x"^"b"."x"^-"b"+"x"^"b"."x"^-"a"`
`=1/("x"^"a"("x"^-"a"+"x"^-"b"))+1/("x"^"b"("x"^-"b"+"x"^-"a")`
`=1/(("x"^-"a"+"x"^-"b")) [1/"x"^"a"+1/"x"^"b"]`
`=1/("x"^-"a"+"x"^-"b") ["x"^-"a"+"x"^-"b"]=1="R"."H"."S".`
APPEARS IN
RELATED QUESTIONS
Compute:
`(2^-9÷2^-11)^3`
Compute:
`(-1/3)^4÷(-1/3)^8xx(-1/3)^5`
Compute:
`9^0xx4^-1÷2^-4`
Compute:
`(27/64)^(-2/3)`
Compute:
`(243)^(2/5)÷(32)^(-2/5)`
Simplify:
`("a"^5"b"^2)/("a"^2"b"^-3`
Simplify:
`"x"^10"y"^6÷"x"^3"y"^-2`
Simplify:
`(-2"x"^(2/3)"y"^(-3/2))^6`
Simplify and express as positive indice:
`("a"^(-2)"b")^(1/2)xx("a""b"^-3)^(1/3)`
Simplify:
`("x"^(2"n"+7).("x"^2)^(3"n"+2))/"x"^(4(2"n"+3)`