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Question
Compute:
`(243)^(2/5)÷(32)^(-2/5)`
Sum
Solution
`(243)^(2/5)÷(32)^(-2/5)`
`=(3xx3xx3xx3xx3)^(2/5)÷(2xx2xx2xx2xx2)^(-2/5)`
`=(3^5)^(2/5)÷(2^5)^(-2/5)`
`=3^(5xx2/5)÷2^(-2/5xx5)=3^2÷2^-2`
`=3^2xx1/2^-2=3^2xx2^(+2)`
`=3xx3xx2xx2=36`
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