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Question
Simplify:
`[(64)^-2]^-3÷[{(-8)^2}^3]^2`
Sum
Solution
`[(64)^-2]^-3÷[{(-8)^2}^3]^2`
`=(2^6)^(-2xx-3÷(-8)^(2xx3xx2`
`=2^(6xx(6)÷(-8)^12`
`=2^(+36)÷(-8)^12`
`=2^(+36)÷[(-2)^3]^12=2^36÷(-2)^36`
`=2^36/(-2)^36=2^36/2^36` (∵36 is even)
`=2^(36-36)=2^0=1` (∵ `"a"^0=1)`
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