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प्रश्न
Consider the carbon compounds having following molecular formula:
(i) C3H6 (ii) C3H8 (iii) C4H6 (iv) C6H6 (v) C6H12
- State the number of double covalent bonds present in C3H6.
- Write the formula of first member of the homologous series to which the carbon compound C4H6 belongs.
- Which one of the above compounds forms a ring structure of carbon atoms?
- Identify, which of the above compounds, is a member of alkane series.
उत्तर
(a) Only 1 double covalent bond is present, other is a triple covalent bond.
(b) C4H6 is an alkyne, The alkynes are a group of chemical compounds with carbon and hydrogen at least one triple bond. With a general molecular formula of Cn H2n-2, where n is any integer higher than 1, the group of compounds is a homologous series.
The first member of this homologous series is ethyne (C2H2). \[\ce{H-C=C-H}\]
(c) C6H6 (Benzene) will form the ring. The structure features triple-altemate double bonds and a six-carbon ring, which is symbolised by a hexagon.
(d) C3H8 is an alkane as it has each carbon bonded to four other atoms through single covalent bonds and follow general formula Cn H2n+2.
संबंधित प्रश्न
The following vegetables are kept in a basket :
Potato, Tomato, Radish, Brinjal, Carrot, Bottle-gourd
Which two of these vegetables correctly represent the homologous structures?
(A) Carrot and Tomato
(B) Potato and Brinjal
(C) Radish and Carrot
(D) Radish and Bottle-gourd
Define a homologous series. Give the name and structural formula of one homologue of the following:
CH3OH
Write the name and molecular formula of the first member of the homologous series of alkynes.
Define homologous series of organic compounds. List its two characteristics. Write the name and formula of the first member of the series of alkenes.
Distinguish between homologous organs and analogous organs. In which category would you place wings of a bird and wings of a bat? Justify your answer giving a suitable reason.
Complete the following table for homologous series of Alkenes.
| Name | Molecular formula | Condensed structural formula | Number of carbon atom | Number of -CH2- units | Boiling point °C |
| Ethene | C2H4 | CH2 = CH2 | 2 | 0 | -102 |
| Propene | C3H6 | CH3–CH = CH2 | 3 | 1 | -48 |
| 1-Butene | C4H8 | CH3–CH2–CH = CH2 | ______ | ______ | -6.5 |
| 1-Pentene | C5H10 | CH3–CH2–CH2–CH = CH2 | ______ | ______ | 30 |
A carbon compound ‘A’ having melting point 156K and boiling point 351K, with molecular formula C2H6O is soluble in water in all proportions.
- Identify ‘A’ and draw its electron dot structure.
- Give the molecular formulae of any two homologues of ‘A’.
Consider the following molecular formulae of carbon compounds:
(i) CH3COOH (ii) CH3OH (iii) C2H6 (iv) C3H4 (v) C4H8
- Which one of these compounds belongs to homologous series of alcohols?
- Identify the compound having triple bond between carbon-carbon atoms.
- Write the molecular formula of the first member of the homologous series to which CH3COOH belongs.
- Write the general formula of the series to which the compound C4H8 belongs.
Name and draw the electron dot structure of first homologue of alkynes series.
Name the third homologue of alcohols.
