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प्रश्न
Construct a rhombus whose diagonals AC = 7.4cm and BD = 6cm.
उत्तर
The diagonals of a rhombus bisect each other.
Steps of Construction:
1) Draw AC = 7.4cm
2) Draw perpendicular bisector to AC which cuts AC at O.
3) From this perpendicular cut OD and OB such that
OD = `"OB" = (1)/(2)"BD" = (1)/(2) xx 6"cm"` = 3cm
4) Join AB, BC, CD and AD
5) ABCD is the required rhombus.
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संबंधित प्रश्न
Construct a rhombus, having given one side = 4.8 cm and one angle = 75o.
Construct a rhombus ABCD, when:
Its one side = 6 cm and ∠A = 60o.
Construct a rhombus ABCD, when:
Diagonal AC = 6.3 cm and diagonal BD = 5.8 cm.
Construct a rhombus ABCD, when:
One side = 5.0 cm and height = 2.6 cm.
Construct a rhombus ABCD, when: Diagonal AC = 6.0 cm and height = 3.5 cm.
Construct a rhombus ABCD, if ;
CD = 5 cm and diagonal BD = 8.5 cm.
Construct a rhombus ABCD, if ;
diagonal AC = 6 cm and diagonal BD = 5.8 cm.
Construct a rhombus ABCD, if ;
diagonal AC = 4.9 cm and diagonal BD = 6 cm.
Construct a rhombus ABCD, if ;
diagonal AC = 6.6 cm and diagonal BD = 5.3 cm.
Construct a rhombus ABCD, given AB = 3.8cm and ∠A = 60°. Measure AC.
