Advertisements
Advertisements
Question
Construct a rhombus whose diagonals AC = 7.4cm and BD = 6cm.
Solution
The diagonals of a rhombus bisect each other.
Steps of Construction:
1) Draw AC = 7.4cm
2) Draw perpendicular bisector to AC which cuts AC at O.
3) From this perpendicular cut OD and OB such that
OD = `"OB" = (1)/(2)"BD" = (1)/(2) xx 6"cm"` = 3cm
4) Join AB, BC, CD and AD
5) ABCD is the required rhombus.
APPEARS IN
RELATED QUESTIONS
Construct a rhombus, having given one side = 4.8 cm and one angle = 75o.
Construct a rhombus ABCD, when:
One side = 5.4 cm and one diagonal is 7.0 cm.
Construct a rhombus ABCD, when:
One side = 5.0 cm and height = 2.6 cm.
Construct a rhombus ABCD, when: Diagonal AC = 6.0 cm and height = 3.5 cm.
Construct a rhombus ABCD, if ;
AB = 4 cm and ∠B = 120°.
Construct a rhombus ABCD, if ;
BC = 4.7 cm and ∠B = 75°.
Construct a rhombus ABCD, if ;
diagonal AC = 6 cm and diagonal BD = 5.8 cm.
Construct a rhombus ABCD, if ;
diagonal AC = 6.6 cm and diagonal BD = 5.3 cm.
Construct a rhombus ABCD, given AB = 3.8cm and ∠A = 60°. Measure AC.
Construct a rhombus whose side AB = 5cm and diagonal AC = 6cm. MEasure DB and AD.
