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महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

Construct a Word Problem on Quadratic Equation, Such that One of Its Answers is 20 (Years, Rupees, Centimetre Etc.). Also Solve It - Algebra

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प्रश्न

Construct a word problem on quadratic equation, such that one of its answers is 20 (years, rupees, centimeter, etc.). Also, solve it.

बेरीज

उत्तर

Find the roots of a equation  x² - 10x  = 200 

x² - 10x  = 200

=> x² - 10x - 200 = 0

=> x² - 20x + 10x - 200 = 0

=> x(x - 20) + 10(x - 20) = 0

=> (x + 10)(x-20) = 0

=> x = 20  or x = -10

hence one of its answer is 20

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2018-2019 (July) Set 1

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संबंधित प्रश्‍न

Which of the following is a quadratic equation? 

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(c)` x^2+1/x^2=5`                      (d) `2x^2-5x=(x-1)^2`


If the product of the roots of the equation `x^2-3x+k=10`  is-2 then the value of k is
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If the equation `x^2-5x+1=0` has no real roots then 

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(b)`k>2` 

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Form a quadratic equation such that one of its roots is 5. Form a quadratic equation for it and write. (For the formation of word problems you can use quantities like age, rupees, or natural numbers.) (Sample solution for the above example is given below students can take another number to form another example)
Solution:
We need one of the solutions of the quadratic equation as 5.
Then we can take another root as any number like a positive or negative number or zero. Here I am taking another root of the quadratic equation as 2.
Then we can form a word problem as below,
Smita is younger than her sister Mita by 3 years (5 – 2 = 3). If the product of their ages is (5 × 2 = 10). Then find their present ages. 
Let the age of Mita be x.
Therefore age of Smita = x – 3 
By the given condition,
x(x – 3) = 10
x2 – 3x – 10 = 0


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