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प्रश्न
Construct a ΔABC in which BC = 3.6 cm, AB + AC = 4.8 cm and ∠B = 60°.
उत्तर
Steps of construction:
1. Draw a line segment BC of 3.6cm.
2. At the point B, draw `∠`xBC of 60°
3. With center B and radius 4.8cm, draw an arc which intersects XB at D.
4. Join DC
5. Draw the perpendicular bisector of DC which intersects DB at A.
6. Join AC
Hence ΔABCis the required triangle
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