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प्रश्न
Construct an isosceles triangle in which the lengths of each of its equal sides is 6.5 cm and the angle between them is 110°.
उत्तर
An isosceles triangle PQR has to be constructed with PQ = QR = 6.5 cm. A rough sketch of the required triangle can be drawn as follows.
The steps of construction are as follows.
1) Draw the line segment QR of length 6.5 cm.
2) At point Q, draw a ray QX making an angle 110° with QR.
3) Taking Q as centre, draw an arc of 6.5 cm radius. It intersects QX at point P.
4) Join P to R to obtain the required triangle PQR.
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