Advertisements
Advertisements
प्रश्न
Construct ΔABC with BC = 7.5 cm, AC = 5 cm and m∠C = 60°.
उत्तर
A rough sketch of the required triangle is as follows.
The steps of construction are as follows.
1) Draw a line segment BC of length 7.5 cm.
2) At point C, draw a ray CX making 60º with BC.
3) Taking C as centre, draw an arc of 5 cm radius. It intersects CX at point A
4) Join A to B to obtain triangle ABC.
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Construct ΔDEF such that DE = 5 cm, DF = 3 cm and m∠EDF = 90°.
Construct an isosceles triangle in which the lengths of each of its equal sides is 6.5 cm and the angle between them is 110°.
Draw an isosceles triangle with each of equal sides of length 3 cm and the angle between them as 45°.
