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प्रश्न
Convert the given frequency distribution into a continuous grouped frequency distribution:
| Class interval | Frequency |
| 150 – 153 | 7 |
| 154 – 157 | 7 |
| 158 – 161 | 15 |
| 162 – 165 | 10 |
| 166 – 169 | 5 |
| 170 – 173 | 6 |
In which intervals would 153.5 and 157.5 be included?
उत्तर
It is clear that, the given table is in inclusive (discontinuous) form.
So, we first convert it into exclusive form.
Now, consider the classes 150 – 153, 154 – 157.
Lower limit of 154 – 157 = 154 and upper limit of 150 – 153 = 153
Required difference = 154 – 153 = 1
So, half the difference = `1/2` = 0.5
So, we subtract 0.5 from each lower limit and add 0.5 to each upper limit.
The table for continuous grouped frequency distribution is given below:
| Class interval | Frequency |
| 149.5 – 153.5 | 7 |
| 153.5 – 157.5 | 7 |
| 157.5 – 161.5 | 15 |
| 161.5 – 165.5 | 10 |
| 165.5 – 169.5 | 5 |
| 169.5 – 173.5 | 6 |
Thus, 153.5 and 157.5 would use in the class intervals 153.5 – 157.5 and 157.5 – 161.5, respectively.
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