मराठी

Derive the relationship between ∆H and ∆U for an ideal gas. Explain each term involved in the equation. - Chemistry

Advertisements
Advertisements

प्रश्न

Derive the relationship between ∆H and ∆U for an ideal gas. Explain each term involved in the equation.

दीर्घउत्तर

उत्तर

We know that the change in internal energy equals the heat absorbed at constant volume, i.e., U = qV.m. However, the majority of chemical reactions are carried out in flasks or test tubes under constant atmospheric pressure U = qp – PV under constant pressure, where qp is the heat absorbed by the system and – PV is the expansion work done by the system.

Let's call the beginning state with subscript 1 and the end state with subscript 2.

The above equation can be rewritten as

U2 – U1= P(V2 – V1)

On rearranging, we get

qp = (U2 + pV2) – (U1 + pV1)   .......(1)

Now, we can define another thermodynamic function, the enthalpy H [Greek word enthalpies, to warm or heat content] as:

H = U + pV  ......(2)

So, equation (1) becomes

qp = H2 – H1 = ΔH

Despite the fact that q is a path-dependent function, H is a state function because it is reliant on state functions U, p, and V. As a result, H is path-independent. As a result, qp is path-independent.

Equation (2) can be written as for finite changes at constant pressure.

ΔH = ΔU + ΔpV

Since, P is constant, we can write:

ΔH = ΔU + PΔV  ......(3)

It's worth noting that we're actually measuring changes in the enthalpy when heat is absorbed by the system at constant pressure. Remember ΔH= qp , heat absorbed by the system at constant pressure. H is negative for exothermic reactions, which produce heat, and positive for endothermic reactions, which absorb heat from the environment.

As a result, equation (3) becomes U = qv at constant volume (V = 0).

ΔH = ΔU = qv

Let's have a look at a gaseous reaction. If VA is the total volume of gaseous reactants, VB is the total volume of gaseous products, nA is the number of moles of gaseous reactants, and nB is the number of moles of gaseous products, then we write using the ideal gas law.,

PVA = nART

PVB = nBRT

Thus, PVB – PVA = nBRT – nART = (nB – nA)RT

Or, P(VB – VA) = (nB – nA)RT

Or, pΔV = ΔngRT  ......(4)

The number of moles of gaseous products minus the number of moles of gaseous reactants is denoted by ng.

Equation (3) is obtained by substituting the value of PV from equation (4) in equation (3).

ΔH = ΔU + ΔngRT  ......(5)

shaalaa.com
Enthalpy Change, ∆_rH of a Reaction - Reaction Enthalpy - Thermochemical Equations
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 6: Thermodynamics - Multiple Choice Questions (Type - I) [पृष्ठ ७७]

APPEARS IN

एनसीईआरटी एक्झांप्लर Chemistry [English] Class 11
पाठ 6 Thermodynamics
Multiple Choice Questions (Type - I) | Q 58 | पृष्ठ ७७
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×