Advertisements
Advertisements
प्रश्न
Describe the motion of a body which is accelerating at a constant rate of 10 m s–2. If the body starts from rest, how much distance will it cover in 2 s ?
उत्तर
We have to find the distance travelled by the body. We have the following information given,
So, Initial velocity, (u) = 0 m/s
Acceleration, (a) = 10 m/s2
Time taken, (t) = 2 s
We can calculate the distance travelled by using the 2nd equation of motion,
`s = ut + 1/2 at^2`
Put the values in above equation to find the distance travelled by the body,
`(s) = 0(2) + 1/2(10)(2)^2`
= 20 m
APPEARS IN
संबंधित प्रश्न
Give one example of a situation in which a body has a certain average speed but its average velocity is zero.
What term is used to denote the change of velocity with time ?
Explain why, the motion of a body which is moving with constant speed in a circular path is said to be accelerated.
A body starting from rest travels with uniform acceleration. If it travels 100 m in 5 s, what is the value of acceleration ?
Derive the formula s= `ut+1/2at^2` , where the symbols have usual meanings.
A train starting from stationary position and moving with uniform acceleration attains a speed of 36 km per hour in 10 minutes. Find its acceleration.
Which of the following could not be a unit of acceleration?
A bus increases its speed from 36 km/h to 72 km/h in 10 seconds. Its acceleration is :
The slope of a speed-time graph gives:
Draw a velocity versus time graph of a stone thrown vertically upwards and then coming downwards after attaining the maximum height.