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Describe the structure of diborane. - Chemistry

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प्रश्न

Describe the structure of diborane.

थोडक्यात उत्तर

उत्तर

In diborane, two BH2 units are linked by two bridged hydrogens. Therefore, it has eight B-H bonds. However, diborane has only 12 valance electrons and are not sufficient to form normal covalent bonds. The four-terminal B-H bonds are normal covalent bonds (two centre – two-electron bond or 2c-2e bond). The remaining four electrons have to used for the bridged bonds, i.e. two-three centred B-H-B bonds utilise two electrons each.

Hence, these bonds are three centre – two-electron bonds. The bridging hydrogen atoms are in a plane as shown in the figure. In dibome, the boron is sp3 hybridised. Three of the four sp3 hybridised orbitals contains a single electron and the fourth orbital is empty.

Two of the half-filled hybridised orbitals of each boron overlap with the two hydrogens to form four-terminal 2c-2e bonds, leaving one empty and one half filled hybridised orbitals on each boron. The Three centre – two-electron bonds, B-H-B bond formation involves overlapping the half-filled hybridised orbital of one boron, the empty hybridised orbital of the other boron and the half-filled 1s orbital of hydrogen.


                       Structure of diborane

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Group 13 (Boron Group) Elements
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पाठ 2: p-Block Elements - I - Evaluation [पृष्ठ ५५]

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सामाचीर कलवी Chemistry - Volume 1 and 2 [English] Class 12 TN Board
पाठ 2 p-Block Elements - I
Evaluation | Q 8. | पृष्ठ ५५
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