Question

Divide 45x³y²z⁴ by (−15xyz)

Answer 1

${\displaystyle \frac{45x^3{y}^2{z}^4}{-15xyz}=\frac{45}{-15}{x}^{3-2}{y}^{2-1}{y}^{4-1}{z}^{4-1}}$

= −3x²yz³