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प्रश्न
Divide:
9x3 − 6x2 by 3x
बेरीज
उत्तर
9x3 − 6x2 by 3x
= `(9"x"^3-6"x"^2)/(3"x")`
= `(9"x"^3)/(3"x")-(6"x"^2)/(3"x")`
= 3x3−1 − 2x2−1
= 3x2 − 2x
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