Advertisements
Advertisements
प्रश्न
Draw a line segment of length 7.5 cm and divide it in the ratio 1:3.
उत्तर
Steps of Construction:
- Draw a line segment AB of length 7.5 cm.
- Draw ray AX, making an acute angle with AB.
- Mark 4 (i.e., 1 + 3) points as A1, A2, A3, A4 on AX such that AA1 = A1A2 = A2A3 = A3A4.
- Join BA4.
- Through A1 (Since we need 1 part to 3 parts) draw CA1 parallel to BA4, where C lies on AB.
Now, AC:CB = 1:3
APPEARS IN
संबंधित प्रश्न
Construct the circumcircle and incircle of an equilateral triangle ABC with side 6 cm and centre O. Find the ratio of radii of circumcircle and incircle.
Draw a triangle ABC with BC = 7 cm, ∠B = 45° and ∠A = 105°. Then construct a triangle whose sides are`4/5` times the corresponding sides of ΔABC.
Construct a triangle ABC with BC = 7 cm, ∠B = 60° and AB = 6 cm. Construct another triangle whose sides are `3/4` times the corresponding sides of ∆ABC.
Draw a line segment of length 7 cm and divide it internally in the ratio 2 : 3.
Construct the circumcircle and incircle of an equilateral ∆XYZ with side 6.5 cm and centre O. Find the ratio of the radii of incircle and circumcircle.
Draw a line segment AB of length 7 cm. Using ruler and compasses, find a point P on AB such that `(AP)/(AB)=3/5`.
Δ SHR ∼ Δ SVU. In Δ SHR, SH = 4.5 cm, HR = 5.2 cm, SR = 5.8 cm and
SHSV = 53 then draw Δ SVU.
Find the co-ordinates of the centroid of the Δ PQR, whose vertices are P(3, –5), Q(4, 3) and R(11, –4)
To construct a triangle similar to a given ΔABC with its sides `8/5` of the corresponding sides of ΔABC draw a ray BX such that ∠CBX is an acute angle and X is on the opposite side of A with respect to BC. Then minimum number of points to be located at equal distances on ray BX is ______.
A point C divides a line segment AB in the ratio 5 : 6. The ratio of lengths AB: BC is ______.
