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प्रश्न
Draw a line segment of length 7.5 cm and divide it in the ratio 1:3.
उत्तर
Steps of Construction:
- Draw a line segment AB of length 7.5 cm.
- Draw ray AX, making an acute angle with AB.
- Mark 4 (i.e., 1 + 3) points as A1, A2, A3, A4 on AX such that AA1 = A1A2 = A2A3 = A3A4.
- Join BA4.
- Through A1 (Since we need 1 part to 3 parts) draw CA1 parallel to BA4, where C lies on AB.
Now, AC:CB = 1:3
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संबंधित प्रश्न
Construct a triangle similar to a given ΔABC such that each of its sides is (5/7)th of the corresponding sides of Δ ABC. It is given that AB = 5 cm, BC = 7 cm and ∠ABC = 50°.
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If the point P (6, 7) divides the segment joining A(8, 9) and B(1, 2) in some ratio, find that ratio
Solution:
Point P divides segment AB in the ratio m: n.
A(8, 9) = (x1, y1), B(1, 2 ) = (x2, y2) and P(6, 7) = (x, y)
Using Section formula of internal division,
∴ 7 = `("m"(square) - "n"(9))/("m" + "n")`
∴ 7m + 7n = `square` + 9n
∴ 7m – `square` = 9n – `square`
∴ `square` = 2n
∴ `"m"/"n" = square`
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