Advertisements
Advertisements
प्रश्न
Draw an angle ABC = 60°. Draw the bisector of it. Also, draw a line parallel to BC a distance of 2.5 cm from it.
Let this parallel line meet AB at point P and angle bisector at point Q. Measure the length of BP and PQ. Is BP = PQ?
उत्तर
Steps of construction :
- Draw, ∠ABC = 60°
- Draw BD, the bisector of ∠ABC.
- Taking B as centre, draw an arc of radius 2.5 cm.
- Taking C as a centre, draw another arc of radius 2.5 cm.
- Draw a line MN that touches these two arcs drawn. Then MN is the required line parallel to BC.
- Let this line MN meets AB at P and bisector BD at Q.
- Measure BP and PQ.
By measurement, we see BP = PQ.
APPEARS IN
संबंधित प्रश्न
Draw a line AB = 6 cm. Mark a point P anywhere outside the line AB. Through point P, construct a line parallel to AB.
Draw a line MN = 5.8 cm. Locate a point A which is 4.5 cm from M and 5 cm from N. Through A draw a line parallel to line MN.
Draw a straight line AB = 6.5 cm. Draw another line which is parallel to AB at a distance of 2.8 cm from it.
Construct an angle PQR = 80°. Draw a line parallel to PQ at a distance of 3 cm from it and another line parallel to QR at a distance of 3.5 cm from it. Mark the point of intersection of these parallel lines as A.
Construct an angle ABC = 90°. Locate a point P which is 2.5 cm from AB and 3.2 cm from BC.
Find the distance between the given lines using a set square at two different points on each of the pairs of lines and check whether they are parallel.
Draw a line segment measuring 7.8 cm. Mark a point B above it at a distance of 5 cm. Through B draw a line parallel to the given line segment
Draw a line and mark a point R below it at a distance of 5.4 cm Through R draw a line parallel to the given line
Draw a line segment AB of length 6 cm. At each end of this line segment AB, draw a line perpendicular to the line AB. Are these lines parallel?