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Draw an Angle Abc = 60°. Draw the Bisector of It. Also, Draw a Line Parallel to Bc a Distance of 2.5 Cm from It. Let this Parallel Line Meet Ab at Point P and Angle Bisector at Point Q. - Mathematics

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Question

Draw an angle ABC = 60°. Draw the bisector of it. Also, draw a line parallel to BC a distance of 2.5 cm from it.
Let this parallel line meet AB at point P and angle bisector at point Q. Measure the length of BP and PQ. Is BP = PQ?

Sum

Solution

Steps of construction :

  1. Draw, ∠ABC = 60°
  2. Draw BD, the bisector of ∠ABC.
  3. Taking B as centre, draw an arc of radius 2.5 cm.
  4. Taking C as a centre, draw another arc of radius 2.5 cm.
  5. Draw a line MN that touches these two arcs drawn. Then MN is the required line parallel to BC.
  6. Let this line MN meets AB at P and bisector BD at Q.
  7. Measure BP and PQ.
    By measurement, we see BP = PQ.
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Construction of an Angle - Construction of Parallel Lines
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Chapter 18: Constructions - Exercise 18 (C) [Page 205]

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Selina Concise Mathematics [English] Class 8 ICSE
Chapter 18 Constructions
Exercise 18 (C) | Q 5 | Page 205
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