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प्रश्न
Draw ΔRSP ∼ ΔTQP. In ΔTQP, TP = 5 cm, ∠P = 50°, PQ = 4.5 cm and `("RS")/("TQ") = 2/3`.
उत्तर
Steps of construction:
- Draw segment PQ = 4.5 cm.
- Draw ray PX such that ∠XPQ = 50°.
- Take point T on ray PX such that PT = 5 cm.
- Join TQ. ΔTQP is obtained.
- Divide segment PQ into 3 equal parts.
- Fix point S on PQ such that the length of PS is `2/3` of the length of segment PQ.
- Draw a line parallel to side TQ through S.
- Name the point of intersection of the line and ray PT as R. Thus, we get the required ΔRSP similar to ΔTQP.
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