Advertisements
Advertisements
प्रश्न
Draw the graph for the linear equation given below:
3x + 2y = 0
उत्तर
First prepare a table as follows:
| x | -1 | 0 | 1 |
| y | `(3)/(2)` | 0 | -`(3)/(2)` |
Thus the graph can be drawn as follows:
APPEARS IN
संबंधित प्रश्न
Draw the graph for the linear equation given below:
x = 0
Draw the graph for the linear equation given below:
5x+ y = 0.
Draw the graph for the linear equation given below:
4x - y = 0
Draw the graph for the linear equation given below:
y = `(2x)/(3) - 1`
Draw the graph for the linear equation given below:
`(x - 1)/(3) - (y + 2)/(2) = 0`
Draw the graph for the equation given below:
`(2x - 1)/(3) - (y - 2)/(5) = 0`
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
7 - 3 (1 - y) = -5 + 2x
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
y = x - 3
y = - x + 5
On the same graph paper, plot the graphs of y = 2x - 1, y = 2x and y = 2x + 1 from x = - 2 to x = 4. Are the graphs (lines) drawn parallel to each other?
Use the graphical method to show that the straight lines given by the equations x + y = 2, x - 2y = 5 and `x/(3) + y = 0` pass through the same point.
