मराठी

Evaluate: ∫exsinx dx -

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प्रश्न

Evaluate:

exsinx dx

बेरीज

उत्तर

Let I = exsinx dx   ....(1)

Integrating by parts,

I = exsinx dx-(sinx dxddxex)dx

= ex(-cosx)--cosxexdx

= -excosx+excosx dx

Again integrating by parts,

I = -excosx+excosx dx-(cosx dxddxex)dx

I = -excosx+exsinx-sinxexdx

∴ I = -excosx+exsinx-I  ....[From (1)]

∴ 2I = -ex(cosx-sinx)+c1

∴ I = ex2(sinx-cosx)+c (where c=c12)

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