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प्रश्न
Evaluate Δ(log ax)
बेरीज
उत्तर
Δ log (ax) = log (ax + h) – log ax
= `log [("a"x + "h")/("a"x)]`
= `log[("a"x)/("a") + "h"/("a"x)]`
= `log [1 + "h"/("a"x)]`
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Finite Differences
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