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प्रश्न
Expand : `(3"x"+1/(3"x"))^2`
बेरीज
उत्तर
`(3"x"+1/(3"x"))^2=(3"x")^2+(1/(3"x")) ^2+2xx3"x"xx 1 /(3"x")`
`=9"x"^2+1/(9"x"^2)+2`
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Important Formula of Expansion
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Expand : (3x – 4y + 5z)2
