Advertisements
Advertisements
Question
Expand : `(3"x"+1/(3"x"))^2`
Sum
Solution
`(3"x"+1/(3"x"))^2=(3"x")^2+(1/(3"x")) ^2+2xx3"x"xx 1 /(3"x")`
`=9"x"^2+1/(9"x"^2)+2`
shaalaa.com
Important Formula of Expansion
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Expand : `(2"a"-1/"a")^2`
Expand : `(2"x"-1/(2"x"))^2`
Find the square of `3"x"+2/"y"`
Find the square of `"5a"/"6b"-"6b"/"5a"`
Find the square of `5"x"+1/(5"x")`
If `"a" +1/"a"=2`, find : `"a"^2+1/"a"^2`
If a2 + b2 = 41 and ab = 4, find : a + b
If `2"a"+1/(2"a")=8`, find : `4"a"^2+1/(4"a"^2)`
If `2"a"+1/(2"a")=8`, find : `16"a"^4+1/(16"a"^4)`
If `3"x"-1/(3"x")=5`, find : `9"x"^2+1/(9"x"^2)`
