Advertisements
Advertisements
Question
Expand : `(2"a"-1/"a")^2`
Sum
Solution
`(2"a"-1/"a")^2=(2"a")^2+(1/"a")^2-2xx2"a"xx1/"a"`
`=4"a"^2+1/"a"^2-4`
shaalaa.com
Important Formula of Expansion
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Expand: `("a"+1/(2"a"))^2`
Expand : (a−b+c)2
Find the square of `5"x"+1/(5"x")`
If `"a" +1/"a"=2`, find : `"a"^2+1/"a"^2`
If `"a" +1/"a"=2`, find: `"a"^4+1/"a"^4`
If a2 + b2 = 41 and ab = 4, find : a + b
If `3"x"-1/(3"x")=5`, find : `9"x"^2+1/(9"x"^2)`
If `3"x"-1/(3"x")=5`, find : `81"x"^4+1/(81"x"^4)`
Expand : (3x – 4y + 5z)2
Expand : (2a – 5b – 4c)2