Advertisements
Advertisements
Question
If `"a" +1/"a"=2`, find: `"a"^4+1/"a"^4`
Sum
Solution
`"a"^4+1/"a"^4=("a"^2+1/"a"^2)^2-2`
`=(2)^2-2`
= 4 − 2
= 2
shaalaa.com
Important Formula of Expansion
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Expand : `(2"a"-1/"a")^2`
Expand : (a+b−c)2
Find the square of `"5a"/"6b"-"6b"/"5a"`
Find the square of `5"x"+1/(5"x")`
Find the square of `8"x"+3/2"y"`
If `"a" +1/"a"=2`, find : `"a"^2+1/"a"^2`
If `"m" -1/"m"=5`, find: `"m"^4+1/"m"^4`
If `"m" -1/"m"=5`, find: `"m"^2-1/"m"^2`
If `3"x"-1/(3"x")=5`, find : `81"x"^4+1/(81"x"^4)`
Expand : (3x – 4y + 5z)2
