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प्रश्न
Expand : `(2"a"-1/"a")^2`
बेरीज
उत्तर
`(2"a"-1/"a")^2=(2"a")^2+(1/"a")^2-2xx2"a"xx1/"a"`
`=4"a"^2+1/"a"^2-4`
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Important Formula of Expansion
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