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प्रश्न
Expand : (2a – 5b – 4c)2
बेरीज
उत्तर
(2a – 5b – 4c)2
= (2a)2 + (–5b)2 + (–4c)2 + 2 (2a) (–5b) + 2 (–5b) (–4c) + 2 (–4c) (2a)
= 4a2 + 25b2 + 16c2 – 20ab + 40bc – 16ca
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Important Formula of Expansion
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