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प्रश्न
Find the square of `8"x"+3/2"y"`
बेरीज
उत्तर
`(8"x"+3/2"y")^2=(8"x")^2+(3/2"y")^2+2xx8"x"xx3/2"y"`
`=64"x"^2+9/4"y"^2+24"xy"`
`=64"x"^2+24"xy"+9/4"y"^2`
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