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प्रश्न
Expand (5p – 1)2
बेरीज
उत्तर
(5p – 1)2
Comparing (5p – 1)2 with (a – b)2 we have a = 5p and b = 1
(a – b)2 = a2 – 2ab + b2
(5p – 1)2 = (5p)2 – 2(5p)(1) + 12
= 52p2 – 10p + 1
= 25p2 − 10p + 1
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पाठ 3: Algebra - Exercise 3.3 [पृष्ठ ९१]
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