Advertisements
Advertisements
Question
Expand (5p – 1)2
Sum
Solution
(5p – 1)2
Comparing (5p – 1)2 with (a – b)2 we have a = 5p and b = 1
(a – b)2 = a2 – 2ab + b2
(5p – 1)2 = (5p)2 – 2(5p)(1) + 12
= 52p2 – 10p + 1
= 25p2 − 10p + 1
shaalaa.com
Is there an error in this question or solution?
Chapter 3: Algebra - Exercise 3.3 [Page 91]
APPEARS IN
RELATED QUESTIONS
Factors of 4 – m2 are
The factors of x2 – 4x + 4 are __________
(a – 1)2 = a2 – 1
Expand the following square, using suitable identities
(b – 7)2
Evaluate the following, using suitable identity
472
Square of 3x – 4y is ______.
1032 – 1022 = ______ × (103 – 102) = ______.
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
x2 – 10x + 25
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
p2 – 2p + 1
Verify the following:
(a – b)(a – b)(a – b) = a3 – 3a2b + 3ab2 – b3
