Advertisements
Advertisements
Question
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
p2 – 2p + 1
Sum
Solution
We have,
p2 – 2p + 1 = p2 – 2 · p · 1 + 12
= (p – 1)2
= (p – 1)(p – 1)
shaalaa.com
Is there an error in this question or solution?
Chapter 7: Algebraic Expression, Identities and Factorisation - Exercise [Page 234]
APPEARS IN
RELATED QUESTIONS
Expand `("x"-2/"x")^2`
Expand (7m − 4)2
Expand: (98)2
Show that (m – n)2 + (m + n)2 = 2(m2 + n2)
The factors of x2 – 6x + 9 are
Square of 9x – 7xy is ______.
(a – b)2 + ______ = a2 – b2
Using suitable identities, evaluate the following.
(9.9)2
Factorise the following.
x2 – 10x + 21
Factorise the following.
x2 + 4x – 77