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प्रश्न
Expand the following square, using suitable identities
(xyz – 1)2
बेरीज
उत्तर
(xyz – 1)2
Comparing (xyz – 1)2 with (a – b)2 we have a = xyz and b = 1
(a – b)2 = a2 – 2ab + b2
(xyz – 1)2 = (xyz)2 – 2(xyz)(1) + 12
(xyz – 1)2 = x2y2z2 – 2xyz + 1
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पाठ 3: Algebra - Exercise 3.1 [पृष्ठ ६२]
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