मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Explain Biot Savart's Law. - Physics

Advertisements
Advertisements

प्रश्न

Explain Biot Savart's Law.

Explain Biot and Savart’s law with suitable diagram.

स्पष्ट करा

उत्तर

Statement of Biot Savart's Law: The magnitude of magnetic induction (dB) at a point due to a small element of current carrying conductor is

  1. directly proportional to the current,
  2. directly proportional to the length of the element,
  3. directly proportional to the sine of the angle between the element and the line joining the center of the element to the point and
  4. inversely proportional to the square of the distance of the point from the center of the element
    i.e, `dB prop (Idl sin theta)/r^2`

Explanation:

Consider a small element of length d l of conductor carrying current I.

Let P be any point at distance 'r' from the conductor.

Let θ be the angle between dl and r.

dl - Length of element along the wire

Let dB be the magnetic induction at point P.

By Biot-Savart law,

`dB prop (Idl sin theta)/r^2`

`dB = K (Idl sin theta)/r^2`,

where K is constant and `K = mu_0/(4 pi)`

∴ `dB = mu_0/(4 pi) (Idl sin theta)/r^2`

In vector form,

`dvecB = mu_0/(4 pi) (Ivec(dl) xx vecr)/r^3`

shaalaa.com
Magnetic Field Due to a Current: Biot-savart Law
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 10: Magnetic Effect of Electric Current - Short Answer II

संबंधित प्रश्‍न

Using Biot Savarts law, obtain the expression for the magnetic induction near a straight infinitely long current-carrying wire. 


Which of the following graphs shows the variation of magnetic field B, with distance for a long current carrying conductor?


A long straight wire carries a current of π ampere. The magnetic field due to it will be 10 x `10^-5` weber/m2 at what distance from the wire

0 = permeability of air]?


The value of magnetic induction will be minimum at a point due to a small current carrying conductor when angle between element and line joining point and centre of element is ____________.


The magnetic induction at a point P which is at a distance of 2 cm from a long current-carrying wire is 10-6 T. The induction at a distance 8 cm from same current-carrying wire is ______.


The magnetic field at the centre of coil of n turns, bent in the form of a square of side `2l`, carrying current i, is ____________.


A current 'I' is flowing along an infinite, straight wire, in the positive Z-direction and the same current is flowing along a similar parallel wire 5 m apart, in the negative Z-direction. A point P is at a perpendicular distance 3 m from the first wire and 4 m from the second. What will be magnitude of the magnetic field B at P?


A straight wire carrying current 'I' is bent into a semi-circular arc of radius 'r', as shown. The magnitude of magnetic field at point 'O' due to semi-circular arc is (µ0 = Permeability of free space) ____________.


A current path shaped as shown in figure produces a magnetic field at P, the centre of the arc. If the arc subtends an angle of 30° and the radius of arc is 0.6 m. What is the magnitude of the field at P, if the current is 3.0 A?


A cylindrical cavity of diameter a exists inside a cylinder of diameter 2a as shown in the figure. Both the cylinder and the cavity are infinitely long. A uniform current density J flows along the length. If the magnitude of the magnetic field at the point P is given `"N"/12`µ0aJ, then the value of N is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×