Advertisements
Advertisements
प्रश्न
Explain the following:
Non-polar covalent compounds are insoluble in water.
उत्तर
On the basis of principle like dissolves like we can interpret the insolubility of non polar covalent compounds. Since water is a polar covalent compound that is it has positively and negatively charged ends but the non-polar covalent compounds do not have any kind of charge separation. So water molecules are unable to interact with the molecules of non polar compound and break apart the intermolecular forces of attraction among non-polar molecules making them soluble in water.
APPEARS IN
संबंधित प्रश्न
Explain the bonding in methane molecule using electron dot structure.
What type of chemical bond is formed between carbon and bromine?
What type of bond is present in oxygen molecule?
How buckminsterfullerene is it related to diamond and graphite?
Explain the following briefly.
Pure water does not conduct electricity, but on adding sodium chloride to it, it starts conducting electricity.
Answer the following question.
What is methane? Draw its electron dot structure. Name the type of bonds formed in this compound. Why are such compounds:
(i) poor conductors of electricity? and
(ii) have low melting and boiling points? What happens when this compound burns in oxygen?
Complete the following activity.
Write the names of the hydrocarbons for the following structural formula.
(isobutylene, cyclohexane, propene, cyclohexene, cyclopentane, benzene, propyne, isobutane, propane)
| \[\begin{array}{cc}\phantom{......}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{..}\\ \phantom{.....}|\phantom{....}|\phantom{....}|\\ \ce{H - C - C = C}\\\phantom{.....}|\phantom{.........}|\\ \phantom{.....}\ce{H}\phantom{........}\ce{H}\end{array}\] |
Consider the coordination compound, K2[Cu(CN)4]. A coordinate covalent bond exists between:
`"CH"_3 - "CH"_2 - "OH" overset("Alkaline""KMnO"_4 + "Heat")(->) "CH"_3 - "COOH"`
In the above given reaction, alkaline KMnO4 acts as
The electron dot structure of chlorine molecule is:
