मराठी

Explain the following: COX2 is a better reducing agent below 710 K whereas CO is a better reducing agent above 710 K. - Chemistry

Advertisements
Advertisements

प्रश्न

Explain the following:

\[\ce{CO2}\] is a better reducing agent below 710 K whereas \[\ce{CO}\] is a better reducing agent above 710 K.

दीर्घउत्तर

उत्तर

To Ellingham diagram, at temperature below 710 K,

\[\ce{ΔG^Θ_{(C, CO_2)} < ΔG^Θ_{(C, CO)}}\] hence \[\ce{CO2}\] is better reducing agent.

At temperature above 710 K, \[\ce{ΔG^Θ_{(C, CO_2)} < ΔG^Θ_{(C, CO)}}\] hence \[\ce{CO}\] is better reducing agent.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 6: General Principle and Processes of Isolation of Elements - Multiple Choice Questions (Type - I) [पृष्ठ ८६]

APPEARS IN

एनसीईआरटी एक्झांप्लर Chemistry [English] Class 12
पाठ 6 General Principle and Processes of Isolation of Elements
Multiple Choice Questions (Type - I) | Q 55.(a) | पृष्ठ ८६

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×