मराठी

Explain the following reactions: Wolff Kishner reduction - Chemistry

Advertisements
Advertisements

प्रश्न

Explain the following reactions:

Wolff Kishner reduction

स्पष्ट करा

उत्तर

In this reaction, the reduction of carbonyl compounds to hydrocarbons takes place by heating them with hydrazine and a base to form hydrazine which is further reduced to form a methylene group along with nitrogen gas.

\[\begin{array}{cc}
\phantom{..}\ce{R}\phantom{.........................}\ce{R}\phantom{.......................}\ce{R}\phantom{................}\\
\phantom{..}\backslash\phantom{.........................}\backslash\phantom{........................}\backslash\phantom{.............}\\
\phantom{....}\ce{C = \underset{Hydrazine}{O + H2N - NH2} -> C = N - NH2 ->[glycol + KOH][180°C] CH2 + N2(g)}\\
\phantom{..}/\phantom{.........................}/\phantom{........................}/\phantom{.............}\\
\phantom{.........}\ce{\underset{Carbonyl compound}{R'}}\phantom{..................}\ce{R'}\phantom{...................}\ce{\underset{Hydrocarbon}{R'}}\phantom{........................}
\end{array}\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2021-2022 (April) Term 2 - Delhi Set 1

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×