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प्रश्न
Explain why, diamond has a high melting point.
उत्तर
Diamonds has a very high melting point, as a huge amount of heat energy is required to break the strong covalent bonds in one crystal of a diamond. The melting point of diamonds is above 3500oC.
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संबंधित प्रश्न
Write the number of covalent bonds in the molecule of butane, C4H10.
Name a carbon containing molecule which has two double bonds.
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Give the formula of the compound that would be formed by the combination of the following pair of elements:
K and H
What type of bonding would you expect between Carbon and Chlorine?
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what substance is graphite made?
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Complete the following:
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Compound X consists of molecules.
Choose the letter corresponding to the correct answer from the options A, B, C and D given below:
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Compound X consists of molecules.
Choose the letter corresponding to the correct answer from the options A, B, C and D given below:
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Element A has 2 electrons in its M shell. Element B has atomic number 7.
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Name two compounds that are covalent when taken pure but produce ions when dissolved in water.
Complete the following activity.
Write the names of the hydrocarbons for the following structural formula.
(isobutylene, cyclohexane, propene, cyclohexene, cyclopentane, benzene, propyne, isobutane, propane)
| \[\begin{array}{cc}\phantom{......}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{..}\\ \phantom{.....}|\phantom{....}|\phantom{....}|\\ \ce{H - C - C = C}\\\phantom{.....}|\phantom{.........}|\\ \phantom{.....}\ce{H}\phantom{........}\ce{H}\end{array}\] |
Acetic acid was added to a solid X kept in a test tube. A colourless, odourless gas Y was evolved. The gas was passed through lime water, which turned milky. It was concluded that ______.
Which of the following are correct structural isomers of butane?
- \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - C - H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
\end{array}\] - \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - H}\\
|\phantom{.....}|\phantom{.....}|\\
\ce{H}\ce{H-C-H}\ce{H}\\
|\\
\ce{H}\\
\end{array}\] - \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - H}\\
|\phantom{.....}\backslash\phantom{..}|\\
\phantom{....}\ce{H}\phantom{......}\ce{C - H}\phantom{}\\
\phantom{.......}|\\
\phantom{.......}\ce{H}\\
\end{array}\] - \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\\
\ce{H - C - C - H}\\
|\phantom{....}|\\
\ce{H - C - C - H}\\
|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\\
\end{array}\]
