Advertisements
Advertisements
प्रश्न
Express the following in m s-1.
18 km min-1
उत्तर
18 km min-1
1 km = 1000 m
1 min = 60 s
∴ 18 km min-1 = `18 xx 1000/60` = 300 ms-1
APPEARS IN
संबंधित प्रश्न
Name the physical quantity obtained by dividing ‘Distance travelled’ by ‘Time taken’ to travel that distance.
State whether speed is a scalar or a vector quantity. Give reason for your choice.
The distance between Delhi and Agra is 200 km. A train travels the first 100 km at a speed of 50 km/h. How fast must the train travel the next 100 km, so as to average 70 km/h for the whole journey ?
Give one example of a motion where an object does not change its speed but its direction of motion changes continuously.
The speed of a moving object is determined to be 0.06 m/s. This speed is equal to :
A car is moving with a velocity 20 m s-1. The brakes are applied to retard it at a rate of 2 m s-2. What will be the velocity after 5 s of applying the brakes?
A train travels with a speed of 60 km h-1 from station A to station B and then comes back with a speed 80 km h-1 from station B to station A. Find -
- The average speed
- The average velocity of the train.
A train is moving with a velocity of 90 km h-1 . It is brought to stop by applying the brakes which produce a retardation of 0.5 ms-2 Find :
(i) The velocity after 10 s , and
(ii) the time taken by the train to come to rest .
Write down the type of motion of a body along with the A – O – B of the following distance – time graph.
Derive th e equation of motion.
S = ut+ `1/2` at2,
Where the symbols have their usual meanings