Advertisements
Advertisements
प्रश्न
Factorise:
`(8"a"^3)/27 - "b"^3/8`
बेरीज
उत्तर
`(8"a"^3)/27 - "b"^3/8`
= `((2"a")/3)^3 - ("b"/2)^3`
= `( (2"a")/3 - "b"/2 )[((2"a")/3)^2 + (2"a")/3 xx "b"/2 + ("b"/2)^2 ]` ...[∵ a3 - b3 = (a - b)(a2 + ab + b2)]
= `((2"a")/3 - "b"/2)["4a"^2/9 + ("ab")/3 + "b"^2/4]`
shaalaa.com
Method of Factorisation : the Sum Or Difference of Two Cubes
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Factorise:
a3 - 27
Factorise : 1 - 8a3
Factorise : a6 + 27b3
Factorise : 3x7y - 81x4y4
Factorise: (x - y)3 - 8x3
Factorise:
a4 - 343a
Show that : 133 - 53 is divisible by 8
Factorise : a6 - 7a3 - 8
Factorise:
a3 - 27b3 + 2a2b - 6ab2
Evaluate :
`[ 5.67 xx 5.67 xx 5.67 + 4.33 xx 4.33 xx 4.33 ]/[5.67 xx 5.67 - 5.67 xx 4.33 + 4.33 xx 4.33]`
