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प्रश्न
Factorise the following:
`2x^2 + x/(6) - 1`
बेरीज
उत्तर
`2x^2 + x/(6) - 1`
= `(1)/(6) (12x^2 + x - 6)`
= `(1)/(6) (12x^2 + 9x - 8x - 6)`
= `(1)/(6) [3x(4x + 3) - 2(4x + 3)]`
= `(1)/(6) [(4x + 3) (3x - 2)]`
= `(1)/(6)(4x + 3) (3x - 2)`.
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