Advertisements
Advertisements
प्रश्न
Factorise the following:
(a2 - b2)(c2 - d2) - 4abcd
उत्तर
(a2 - b2)(c2 - d2) - 4abcd
= a2c2 - a2d2 - b2c2 + b2d2 - 4abcd
= a2c2 + b2d2 - 2abcd - a2d2 - b2c2 - 2abcd
= (a2c2 + b2d2 - 2abcd) - (a2d2 + b2c2 + 2abcd)
= (ac - bd)2 - (ad + bc)2
= [(ac - bd) + (ad + bc)][(ac - bd) - (ad + bc)]
= (ac - bd + ad + bc)(ac - bd - ad - bc).
APPEARS IN
संबंधित प्रश्न
Factorise : 25a2 - 9b2
Factorise : 9(a - 2)2 - 16(a + 2)2
Factorise : (a + b)3 - a - b
Factorise : x4 + x2 + 1
Factorise the following by the difference of two squares:
x6 - 196
Factorise the following by the difference of two squares:
8xy2 - 18x3
Factorise the following by the difference of two squares:
a(a - 1) - b(b - 1)
Factorise the following by the difference of two squares:
(x - 2y)2 -z2
Factorise the following:
25(x - y)2 - 49(c - d)2
Factorise the following:
4x2 - 12ax - y2 - z2 - 2yz + 9a2