मराठी

Factorise : 9(A - 2)2 - 16(A + 2)2 - Mathematics

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प्रश्न

Factorise : 9(a - 2)2 - 16(a + 2)2

बेरीज

उत्तर

 9(a - 2)2 - 16(a + 2)2
= [3 (a - 2)]2 - [4(a + 2)]2

= [3 (a - 2) + 4 (a + 2)] [3(a - 2) - 4(a + 2)]     ...[∵ a2 - b2 = (a + b)(a - b)]

= [3a - 6 + 4a + 8] [3a - 6 - 4a - 8]

= (7a + 2)(- a - 14)

= - (7a + 2)(a + 14)

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Method of Factorisation : Difference of Two Squares
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Factorisation - Exercise 5 (C) [पृष्ठ ७२]

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सेलिना Concise Mathematics [English] Class 9 ICSE
पाठ 5 Factorisation
Exercise 5 (C) | Q 8 | पृष्ठ ७२
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