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Question
Factorise : 9(a - 2)2 - 16(a + 2)2
Sum
Solution
9(a - 2)2 - 16(a + 2)2
= [3 (a - 2)]2 - [4(a + 2)]2
= [3 (a - 2) + 4 (a + 2)] [3(a - 2) - 4(a + 2)] ...[∵ a2 - b2 = (a + b)(a - b)]
= [3a - 6 + 4a + 8] [3a - 6 - 4a - 8]
= (7a + 2)(- a - 14)
= - (7a + 2)(a + 14)
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Method of Factorisation : Difference of Two Squares
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