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Question
Factorise : 9a2 + 3a - 8b - 64b2
Sum
Solution
9a2 + 3a - 8b - 64b2
= 9a2 - 64b2 + 3a - 8b
= ( 3a )2 - ( 8b )2 + 3a - 8b
= ( 3a - 8b )( 3a + 8b ) + ( 3a - 8b )
[ ∵ a2 - b2 = ( a + b )( a - b )]
= ( 3a - 8b )( 3a + 8b + 1 )
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Method of Factorisation : Difference of Two Squares
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