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Question
Factorise : 4a2 - 12a + 9 - 49b2
Sum
Solution
4a2 - 12a + 9 - 49b2
= (2a)2 - 12a + (3)2 - 49b2
= (2a)2 - 2(2a)(3) + (3)2 - (7b)2 ...[∵ (a - b)2 = a2 - 2ab + b2]
= (2a - 3)2 - (7b)2
= (2a - 3 - 7b)(2a - 3 + 7b) ...[∵ a2 - b2 = (a + b)(a - b)]
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Method of Factorisation : Difference of Two Squares
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