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Question
Factorise : 3a5 - 108a3
Sum
Solution
3a5 - 108a3
= 3a3( a2 - 36 )
= 3a3[( a )2 - ( 6 )2]
= 3a3( a - 6 )( a + 6 ) [ ∵ a2 - b2 = ( a + b )( a - b )]
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Method of Factorisation : Difference of Two Squares
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